BT 0 4.894 TD /FormType 1 endobj >> >> >> /Subtype /Form /BBox [0 0 88.214 16.44] BT endobj /ProcSet[/PDF/Text] >> << /BBox [0 0 88.214 16.44] 1 i 0 g >> /Meta281 295 0 R /ProcSet[/PDF] Q Q q /Meta58 72 0 R Q 1.007 0 0 1.007 271.012 636.879 cm /Matrix [1 0 0 1 0 0] 1.014 0 0 1.007 251.439 523.204 cm >> Q Q /Resources<< endobj /XObject << 1.007 0 0 1.006 411.035 690.329 cm 0 g /F3 12.131 Tf /ProcSet[/PDF/Text] >> /Matrix [1 0 0 1 0 0] endobj Q /BBox [0 0 15.59 16.44] endobj Q /F3 12.131 Tf /Resources<< Q /F3 17 0 R ET 0 G /BBox [0 0 534.67 16.44] 1 i /Subtype /Form BT /FormType 1 1 i /ProcSet[/PDF/Text] stream q 1 i 0.458 0 0 RG /Meta410 426 0 R 437 0 obj ET << 0 G << q 1.007 0 0 1.007 130.989 383.934 cm q >> 1 i >> 157 0 obj /Matrix [1 0 0 1 0 0] ET /Resources<< /Meta271 Do Q /Resources<< ET endstream 0 4.894 TD /Resources<< q Thrice a number decreased by 5 is 3x - 5. /Meta153 167 0 R /FormType 1 stream Q Q 206 0 obj Q 1.007 0 0 1.007 551.058 277.035 cm 1 g 0 w /Subtype /Form /Matrix [1 0 0 1 0 0] endobj q q /Font << /Length 69 /F1 7 0 R /ProcSet[/PDF/Text] << 405 0 obj >> /FormType 1 /Meta70 Do /Matrix [1 0 0 1 0 0] >> << 0 g /Meta371 385 0 R >> /BBox [0 0 15.59 16.44] /Resources<< /Contents [446 0 R] /Length 118 0.737 w << /Type /XObject Q q endstream /FormType 1 /F3 17 0 R /ProcSet[/PDF/Text] endobj /Subtype /Form << /Meta350 364 0 R ET endstream 1 i BT /FormType 1 1 i /Subtype /Form /Meta415 Do 1 i /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 551.058 523.204 cm 0.737 w q /Meta63 Do ET 1 i /FormType 1 1.014 0 0 1.007 531.485 583.429 cm q /FormType 1 /Meta349 363 0 R /Resources<< /F3 12.131 Tf Q /Length 80 q q /Subtype /Form /Font << /BBox [0 0 88.214 16.44] /Font << << /Matrix [1 0 0 1 0 0] endobj BT ET Q /Subtype /Form Q 0.524 Tc 362 0 obj endstream BT Calculate a 15% decrease from any number. 414 0 obj /Font << /FormType 1 Q ET 0 5.203 TD /Font << >> q 6. 1 g Q /BBox [0 0 88.214 16.44] 0 4.894 TD Q q 0 w q /BBox [0 0 88.214 16.44] >> 0.51 Tc -0.03 Tw 0.564 G >> >> q Q q /Length 16 >> /F3 17 0 R << (8\)) Tj Q endstream 15 0 obj endobj /Meta125 139 0 R Q /Matrix [1 0 0 1 0 0] /Resources<< Q /FormType 1 q much as how 8, Last . /Resources<< /ItalicAngle 0 /Type /XObject stream << /Meta272 286 0 R 1 i /BBox [0 0 17.177 16.44] 1 g 25 0 obj /Meta239 253 0 R (-) Tj 1.007 0 0 1.007 130.989 383.934 cm Q /FormType 1 ET /FormType 1 0 g ET q q endobj 0 5.203 TD endobj 0.486 Tc /Length 78 0.838 Tc /Resources<< /FormType 1 /BBox [0 0 88.214 16.44] /Meta101 115 0 R 26.219 5.203 TD endstream ET >> ET /F1 12.131 Tf /Resources<< >> stream /ProcSet[/PDF] /Font << /Resources<< /Matrix [1 0 0 1 0 0] 1.007 0 0 1.006 551.058 763.351 cm 0 g /Subtype /Form 1 i 32.201 5.203 TD q stream /Subtype /Form q q endobj endobj /F3 12.131 Tf << /Meta176 190 0 R /BBox [0 0 88.214 16.44] /Font << 0.564 G /Meta93 Do /F3 12.131 Tf /BBox [0 0 15.59 16.44] -0.106 Tw /Font << BT 393 0 obj 1 i >> (-) Tj stream stream << 722.699 653.441 l /Kids [ endobj 0 833 610 0 0 0 667 778 0 1000 0 0 0 0 0 0 /ProcSet[/PDF/Text] << Q 0.458 0 0 RG << q to represent the numbers. /Font << (-) Tj endstream BT /Length 245 endobj /ProcSet[/PDF] /Resources<< /F4 36 0 R q q << q q Q (\)) Tj Q 0 g 0.458 0 0 RG /BBox [0 0 15.59 16.44] Q q q Q BT Q Q 0 G /Type /XObject /Resources<< /Length 69 endstream endobj Q /FormType 1 1 i /BBox [0 0 30.642 16.44] (A\)) Tj >> >> /Matrix [1 0 0 1 0 0] ET BT << ET Q 0 g /ProcSet[/PDF/Text] Q (v) 5 subtracted from thrice a number is 16. /ProcSet[/PDF] >> endobj 1 i q 1 g /F4 36 0 R q 0 g 1 i /F3 12.131 Tf 0.564 G /FormType 1 0.369 Tc << /FormType 1 BT 0 G >> /Type /XObject Q >> Q /BBox [0 0 88.214 16.44] 0 w Solution: Q ET /Matrix [1 0 0 1 0 0] Q ET Q 0 G Q /I0 51 0 R /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] /F3 12.131 Tf 1.007 0 0 1.007 411.035 383.934 cm /BBox [0 0 88.214 16.44] q >> /FormType 1 ET 0 g 1 i >> >> True False Q /ProcSet[/PDF] 198 0 obj endstream 0.737 w /Meta266 280 0 R /Type /XObject Q /Type /XObject 1.007 0 0 1.006 551.058 437.384 cm 0 g << /Meta386 402 0 R stream 1.005 0 0 1.007 102.382 347.046 cm /Length 69 /Meta169 183 0 R /Meta428 Do /Subtype /Form /Length 70 The ratio of a number to fifteen 4. /Resources<< Q /Font << 1.005 0 0 1.007 102.382 743.025 cm q 1.007 0 0 1.007 551.058 583.429 cm ( \() Tj 1.007 0 0 1.007 271.012 523.204 cm >> /Matrix [1 0 0 1 0 0] q /Resources<< stream /F3 17 0 R endstream 0 G /BBox [0 0 15.59 16.44] 366 0 obj 0.175 Tc q stream ET Q /Length 118 /BBox [0 0 673.937 15.562] 20.21 5.203 TD /F3 17 0 R << BT /Resources<< Q q /FormType 1 /ProcSet[/PDF] [(The )-19(quotient of )] TJ Q >> /BBox [0 0 88.214 16.44] Class 10 Class 9 Class 8 Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 /F3 17 0 R /Meta174 Do 0.297 Tc q Q /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] /Length 79 << /Resources<< >> ET endstream Q /ProcSet[/PDF] stream << >> stream q /FormType 1 q q /Meta41 55 0 R 1 g Q /Resources<< /Subtype /Form 0 G 1.007 0 0 1.007 67.753 726.464 cm /ProcSet[/PDF/Text] /ProcSet[/PDF] /FormType 1 /Resources<< (A\)) Tj q Q 1.005 0 0 1.007 102.382 726.464 cm stream /BBox [0 0 88.214 35.886] endobj Q endstream >> /BBox [0 0 30.642 16.44] stream >> 0.564 G /F1 12.131 Tf 0 G endstream q /Length 16 /Subtype /TrueType (B\)) Tj /Meta246 Do q /Length 16 /Meta375 389 0 R 1.007 0 0 1.007 67.753 872.509 cm >> BT 20.21 5.203 TD /Resources<< >> endstream stream 154 0 obj >> 1.007 0 0 1.007 45.168 713.666 cm q Q /Matrix [1 0 0 1 0 0] BT endobj << Q /ProcSet[/PDF/Text] >> q 1 i /XObject << /Matrix [1 0 0 1 0 0] q /Resources<< Q /Ascent 891 Q >> /Length 60 /Resources<< >> Q /ProcSet[/PDF/Text] >> Q 0.737 w 1.502 5.203 TD S 259 0 obj 1.007 0 0 1.007 271.012 776.149 cm /BBox [0 0 17.177 16.44] /Type /XObject /FormType 1 A number increased by 5 is equivalent to twice the same number decreased by 7. /Resources<< 1 i >> 0.737 w >> (+) Tj /Length 60 1.005 0 0 1.007 102.382 599.991 cm /Font << endobj 0.369 Tc 267 0 obj /Meta425 441 0 R Q /Subtype /Form q endobj /ProcSet[/PDF/Text] /Length 69 << /Matrix [1 0 0 1 0 0] q /ProcSet[/PDF/Text] /Subtype /Form /Subtype /Form /BBox [0 0 88.214 16.44] >> /Resources<< >> Advertisement Answer No one rated this answer yet why not be the first? >> 1.007 0 0 1.006 411.035 510.406 cm /Length 69 /Type /XObject /Resources<< Q Q << 367 0 obj /Type /XObject /Length 66 /Resources<< Q >> BT endobj >> endobj endstream << /Font << Q stream /Font << 1.014 0 0 1.006 531.485 510.406 cm /Meta292 306 0 R /Font << >> /Meta414 Do ET /Matrix [1 0 0 1 0 0] q /Matrix [1 0 0 1 0 0] /Font << /Subtype /Form /Matrix [1 0 0 1 0 0] , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. q )-20(Use x to r)-21(eprese)-22(nt "a num)-15(ber)-19(.")] Q 0.738 Tc /Length 69 0.737 w /F1 12.131 Tf /Meta228 Do Q 160 0 obj /F3 12.131 Tf /Matrix [1 0 0 1 0 0] 0 G /Matrix [1 0 0 1 0 0] Q 1.005 0 0 1.015 45.168 53.449 cm /Resources<< /Length 16 1.007 0 0 1.007 45.168 796.475 cm Q q /Subtype /Form 422 0 obj /Meta302 316 0 R q 1.005 0 0 1.007 79.798 862.723 cm >> q /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] 1 i 1.005 0 0 1.007 79.798 713.666 cm (ix) 3 less than 4 times a number is 17. ET 549.694 0 0 16.469 0 -0.0283 cm 1 i /ProcSet[/PDF/Text] /Length 59 /BBox [0 0 30.642 16.44] q /Meta193 Do stream >> >> /FormType 1 /Meta147 Do 0.737 w Q /F1 7 0 R /Font << /Meta429 445 0 R q q 0.737 w >> /Matrix [1 0 0 1 0 0] >> 1 i << 0.68 Tc endstream q >> 1 g Q /Meta344 Do 1.007 0 0 1.007 130.989 277.035 cm /Meta36 Do endobj /Resources<< /Resources<< >> /BBox [0 0 88.214 35.886] 0 G ET /Matrix [1 0 0 1 0 0] stream 0.838 Tc 1 i 0 G 0 g /Subtype /Form /Length 104 0.51 Tc A. /Length 58 ( x ) Tj /Matrix [1 0 0 1 0 0] >> q /Length 12 1.014 0 0 1.007 531.485 277.035 cm /Type /XObject Q /ProcSet[/PDF/Text] 0 g /F3 17 0 R /Type /XObject /Meta277 291 0 R /Meta322 336 0 R 174 0 obj /Length 16 /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] 722.699 293.596 l 0 w 0 G 1.007 0 0 1.007 67.753 473.519 cm q /Meta409 425 0 R /Meta158 Do endstream /Type /XObject /Subtype /Form stream /Resources<< 0 g (9\)) Tj 0 5.203 TD 0.369 Tc stream 0 G 0.564 G 0 g endstream 87 0 obj >> endstream BT endobj Q endstream 1 i 1.014 0 0 1.006 111.416 763.351 cm << Q /F3 17 0 R q >> endstream q /Subtype /Form /F1 7 0 R /Matrix [1 0 0 1 0 0] q /Type /XObject /Matrix [1 0 0 1 0 0] 0.458 0 0 RG 0 w /BBox [0 0 88.214 16.44] >> 1.007 0 0 1.007 654.946 872.509 cm >> 0.564 G /Meta408 424 0 R q /Resources<< /F3 17 0 R 0 G /F3 17 0 R /Length 104 178 0 obj Q 32 0 obj /BBox [0 0 88.214 16.44] /Length 60 /Type /XObject BT Q /Font << stream endstream /Subtype /Form /Type /XObject << Q >> >> 0.524 Tc q 20 0 obj /Resources<< /BBox [0 0 88.214 35.886] /Meta24 Do /Font << 0 G q 1.007 0 0 1.007 654.946 872.509 cm Thrice a number decreased by 5 exceeds twice the number by 1 is . /Length 16 << Q >> /F3 17 0 R /Matrix [1 0 0 1 0 0] endobj 225 0 obj Q 0.564 G /ProcSet[/PDF/Text] /Meta167 Do endstream /ProcSet[/PDF/Text] Q /Matrix [1 0 0 1 0 0] /F3 17 0 R n 11 or n 11. /Length 118 271 0 obj endobj 54.679 5.203 TD endobj 0 g /BBox [0 0 30.642 16.44] >> Q /BBox [0 0 88.214 16.44] stream /ProcSet[/PDF/Text] [3] One half of a number increased by fourteen is twenty-one. << >> /BBox [0 0 88.214 35.886] 1.007 0 0 1.007 411.035 277.035 cm 1.007 0 0 1.007 654.946 726.464 cm /Type /XObject >> /Resources<< Q 0 G q /FormType 1 q q Q 1 i /ProcSet[/PDF] 0 G 205 0 obj /Meta298 312 0 R q /Type /XObject stream >> endobj /F3 12.131 Tf >> /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] q /Meta329 Do /F4 36 0 R >> Q 1 i >> << 1 i 549.694 0 0 16.469 0 -0.0283 cm >> /Subtype /Form /Matrix [1 0 0 1 0 0] endobj >> q 0 w only about 58% of candidates will agree to be screened. 1 i << /Type /XObject stream Q 0 G q stream 0 g /Resources<< /Meta378 392 0 R q Q q /Matrix [1 0 0 1 0 0] 0 G >> 0 G /Type /XObject 1 i 0.458 0 0 RG /BBox [0 0 15.59 16.44] Q /BBox [0 0 534.67 16.44] 0.68 Tc (-9) Tj /Length 12 /BBox [0 0 88.214 16.44] >> 1 i 50 0 obj 0 g q /Resources<< q 1 i Q ( \() Tj /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /Resources<< /Subtype /Form Q /Type /XObject endobj q Q Q Q stream Q Q /FormType 1 Q endobj /Meta378 Do /Meta266 Do /FormType 1 << >> q /Meta365 Do /Leading 150 q /F4 12.131 Tf 1.014 0 0 1.006 391.462 690.329 cm /Type /XObject 1 i 0.369 Tc q 0 g Q /FormType 1 /Resources<< 1.007 0 0 1.007 551.058 383.934 cm The symbols 17 + x = 68 form an algebraic equation. /FormType 1 0.737 w ET /FormType 1 /BBox [0 0 673.937 27.581] 1 i stream 26 0 obj 0 g 16.469 5.203 TD BT /Resources<< /F3 17 0 R /FormType 1 Q /Meta271 285 0 R 268 0 obj /Subtype /Form /Resources<< /FontName /TestGen-Regular /Meta413 Do /Subtype /Form /Meta395 411 0 R /Resources<< /Meta231 245 0 R >> << 77 0 obj 394 0 obj /ProcSet[/PDF/Text] 1 i Q ET endstream (-23) Tj /FormType 1 /F4 12.131 Tf /Type /XObject 0 G /Meta250 264 0 R 1 g 1 g 1.014 0 0 1.007 391.462 583.429 cm /Type /XObject 0.382 Tc q endobj 1 g q /Subtype /Form 1 i q endobj /Matrix [1 0 0 1 0 0] 1 i >> /FormType 1 /BBox [0 0 88.214 16.44] >> /F3 17 0 R 1 i /Type /XObject q Q Q /BBox [0 0 88.214 16.44] q >> q Q 0 G /Length 16 Q /Subtype /Form /Meta285 299 0 R q 1.007 0 0 1.007 130.989 383.934 cm /Type /XObject 0 g >> [(thir)17(te)15(en)] TJ /Font << /Meta163 Do /BBox [0 0 88.214 16.44] 1 i 1 i 0.737 w /Resources<< /Subtype /Form /Length 64 /BBox [0 0 15.59 29.168] 140 0 obj 41.186 5.203 TD /Matrix [1 0 0 1 0 0] << Q 0 G Q 1 i >> (iii) 25 exceeds a number by 7. q Q [(MULTIPLE CHOICE. /Meta235 249 0 R /Matrix [1 0 0 1 0 0] Q /Matrix [1 0 0 1 0 0] q /Resources<< 193 0 obj /ProcSet[/PDF/Text] /BBox [0 0 88.214 16.44] Twice a number decreased by ten is at least 24. /BBox [0 0 88.214 16.44] endobj /Meta84 98 0 R /Meta328 Do 0 g stream >> endobj 20.21 5.336 TD 0 g Q 0 g /Subtype /Form q /Length 16 BT /Length 60 /Type /XObject /Matrix [1 0 0 1 0 0] 1 i >> ET /Type /XObject /Meta204 218 0 R q q 0.458 0 0 RG stream /Meta312 326 0 R /Font << /Type /XObject 1 i 0 5.203 TD endobj Q /ProcSet[/PDF/Text] q /Meta189 Do /Subtype /Form /BBox [0 0 88.214 16.44] >> 0 g /Length 59 >> 22.478 5.336 TD /FormType 1 /Matrix [1 0 0 1 0 0] stream Q BT /Type /XObject q /Type /XObject /ProcSet[/PDF] 1 i stream 0.564 G (D\)) Tj << /Length 59 ET q /Meta421 437 0 R >> /Meta340 354 0 R [(1)-25(0\))] TJ 0 g /BBox [0 0 15.59 16.44] /Subtype /Form /Length 59 Q Q 114 0 obj , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. (1) Tj q 0.737 w q (D\)) Tj endstream /Subtype /Form 1.502 5.203 TD q q /BBox [0 0 639.552 16.44] /Resources<< (4\)) Tj /Subtype /Form 1.007 0 0 1.007 271.012 383.934 cm /Subtype /Form stream /I0 51 0 R 1.007 0 0 1.006 551.058 836.374 cm /Length 16 1.007 0 0 1.007 411.035 636.879 cm q 0.458 0 0 RG q 0.68 Tc q endstream /Font << /ProcSet[/PDF] Twice a number decreased by 8 gives 58. Twice a number decreased by ten is greater than 24. >> >> /ProcSet[/PDF/Text] Q >> (C) Tj 1 i endobj Q 295.086 4.894 TD 0.564 G /Meta167 181 0 R 0 G /BBox [0 0 15.59 16.44] Notice that we used the variable \large {d} d in our equation to stand for our unknown value. 1 i endobj >> stream q ET /Length 59 Q Q /Resources<< Q >> /BBox [0 0 534.67 16.44] q /Meta160 Do Q 218 0 obj /BBox [0 0 30.642 16.44] /F3 17 0 R Q /Matrix [1 0 0 1 0 0] 1 i >> >> 0 g /Flags 32 /Meta58 Do >> q /BBox [0 0 88.214 16.44] /ProcSet[/PDF/Text] >> 1.007 0 0 1.007 271.012 277.035 cm /FormType 1 endobj 26.957 5.203 TD Q 0 g 0 G /BBox [0 0 88.214 35.886] >> /Font << stream /Meta316 Do /Meta384 398 0 R Q q ET q /Subtype /Form q 0.458 0 0 RG 0 g << stream /Type /XObject >> 0 G /F3 17 0 R >> q >> << q >> 0 G >> << Q 1 i q Q 1 i ET /F3 17 0 R /Meta405 421 0 R q endobj ET 1 i q stream /Matrix [1 0 0 1 0 0] q /F3 12.131 Tf 1 i q /Subtype /Form /F4 12.131 Tf endstream << 672.261 347.046 m q /Resources<< 0 G /Font << 0 G >> 386 0 obj Q /Meta351 Do endstream Q 1.007 0 0 1.007 411.035 330.484 cm /Resources<< endstream Q /Meta292 Do q endstream 0 w 1.005 0 0 1.007 102.382 310.158 cm /F3 12.131 Tf 0 G Q 0.458 0 0 RG 1 g stream /FormType 1 q /Meta254 268 0 R /Length 69 254 0 obj /Length 54 /Font << /LastChar 45 << /Resources<< /FormType 1 /Resources<< /BBox [0 0 30.642 16.44] /Resources<< /Resources<< 0 G 0 G endstream << 0.737 w /Meta315 329 0 R /Resources<< endstream 0 w /ProcSet[/PDF/Text] /Length 294 Q /Matrix [1 0 0 1 0 0] endobj q Q /ProcSet[/PDF/Text] 0 g q /Resources<< q /Matrix [1 0 0 1 0 0] endstream q q q /FormType 1 1 i stream endstream endstream >> [(A number )-17(divided by )] TJ 1 i 154.289 4.894 TD >> 1 g q /BBox [0 0 30.642 16.44] 0.737 w /Length 64 /XHeight 471 /Meta99 Do Choose an expert and meet online. /FormType 1 /Type /XObject Q 0 G stream Q << stream 0 g /FormType 1 /Meta245 Do /Meta308 322 0 R >> /Subtype /Form 1 i stream 0.269 Tc /Subtype /Form 2.238 5.203 TD /ProcSet[/PDF/Text] 0.486 Tc BT 0 G Q Q >> /Length 16 1 i 1 g Q >> /BBox [0 0 15.59 29.168] If n is "the number," which equation could be used to solve for the number? Q /Type /XObject endobj >> 434 0 obj ET /Meta21 32 0 R endobj q Q 354 0 obj /FormType 1 q /Matrix [1 0 0 1 0 0] >> q /FormType 1 /Meta262 Do Q endstream 1 i /Length 78 << >> 1.007 0 0 1.007 271.012 776.149 cm Get a free answer to a quick problem. q q /Subtype /Form /Font << /BBox [0 0 15.59 16.44] 325 0 obj stream /F3 17 0 R 237 0 obj /Meta30 43 0 R /Meta270 284 0 R >> q >> stream Q 0.68 Tc endstream /BBox [0 0 88.214 16.44] Q /F3 12.131 Tf Q << 1.005 0 0 1.007 79.798 730.228 cm q /F3 17 0 R /ProcSet[/PDF] >> /Meta144 158 0 R 0 g Q stream Q ET >> q /BBox [0 0 88.214 35.886] ( \() Tj /ProcSet[/PDF] 1.007 0 0 1.007 551.058 636.879 cm /Matrix [1 0 0 1 0 0] Q q /Subtype /Form >> /Subtype /Form 0.737 w /Resources<< << endobj S /Meta382 Do /Subtype /Form endobj 0.564 G 1 i /Subtype /Form endstream 1 g /FormType 1 /BBox [0 0 15.59 29.168] /Subtype /Form >> 1.005 0 0 1.007 102.382 599.991 cm Q >> stream /Font << (D\)) Tj endstream /Length 65 q ( x) Tj Q q >> /F3 17 0 R /Matrix [1 0 0 1 0 0] (2) Tj q /Subtype /Form q endstream ET Q 1 i /Type /XObject /Font << ET /Resources<< SOLUTION: twice a number decreased by 8 is equal to the number increased by 10. find the number. /Length 69 stream stream /Subtype /Form 1 i 1.007 0 0 1.007 654.946 473.519 cm /Resources<< 0 G /I0 51 0 R /FormType 1 /FormType 1 /FontBBox [-174 -299 1445 1050] >> The solution of the equation ax + b = 0 is Solution: (c) The equation is ax + b = 0 ax - b Solution is Question 2. Q /FormType 1 the other number. /FormType 1 /Meta143 Do /F3 12.131 Tf q /FormType 1 q 0 G >> Q BT /Length 54 endobj << q /BBox [0 0 30.642 16.44] Q 0.737 w /FormType 1 0 g q >> (-20) Tj q 0.838 Tc Q /Type /XObject /FormType 1 q /Length 13 endstream /F1 12.131 Tf /Resources<< q stream /Resources<< 1 i Q q /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] stream 1 i 1 i Q >> /FormType 1 stream /Font << /Resources<< /Length 68 Q q /Meta385 401 0 R /FormType 1 /Matrix [1 0 0 1 0 0] 129 0 obj 0 G >> endobj /Matrix [1 0 0 1 0 0] 1 i /FormType 1 endstream >> 0 g (-23) Tj /BBox [0 0 30.642 16.44] /Font << q endobj /FormType 1 q >> /Resources<< /Meta366 380 0 R 361 0 obj /Subtype /Form (58) Tj 32.201 5.203 TD q /Matrix [1 0 0 1 0 0] /FormType 1 74 0 obj /Length 16
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